1 )вычислите а )2 корня из 49-3 корня из 25 б )4 корня из 16-2 корня из 81 в )10 корней из 81 \100 г)5...

Тематика Алгебра
Уровень 5 - 9 классы
математика вычисления корни алгебра примеры арифметика квадратные корни дроби умножение сложение вычитание
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1 )вычислите а )2 корня из 49-3 корня из 25 б )4 корня из 16-2 корня из 81 в )10 корней из 81 \100 г)5 корней из 36\25 д )100 корней из 0.04 - 114 корней е ) 1 целая 4 \7 умножить на корень из 4900

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задан 4 месяца назад

2 Ответа

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а) 2√49 - 3√25 = 27 - 35 = 14 - 15 = -1 б) 4√16 - 2√81 = 44 - 29 = 16 - 18 = -2 в) 10√81 / 100 = 109 / 100 = 90 / 100 = 0.9 г) 5√36 / 25 = 56 / 5^2 = 30 / 25 = 1.2 д) 100√0.04 = 1000.2 = 20 е) 1 4/7 √4900 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 70 = 1 4/7 * 70 = 1 4

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ответил 4 месяца назад
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Конечно, давайте разберем каждый из ваших вопросов по очереди.

1) Вычислите:

а) (2 \sqrt{49} - 3 \sqrt{25})

Сначала найдём значения подкоренных выражений: [ \sqrt{49} = 7 \quad \text{и} \quad \sqrt{25} = 5 ]

Теперь подставим эти значения: [ 2 \sqrt{49} - 3 \sqrt{25} = 2 \cdot 7 - 3 \cdot 5 ]

Рассчитаем: [ 2 \cdot 7 = 14 \quad \text{и} \quad 3 \cdot 5 = 15 ]

И таким образом: [ 2 \sqrt{49} - 3 \sqrt{25} = 14 - 15 = -1 ]

Ответ: (-1)

б) (4 \sqrt{16} - 2 \sqrt{81})

Сначала найдём значения подкоренных выражений: [ \sqrt{16} = 4 \quad \text{и} \quad \sqrt{81} = 9 ]

Теперь подставим эти значения: [ 4 \sqrt{16} - 2 \sqrt{81} = 4 \cdot 4 - 2 \cdot 9 ]

Рассчитаем: [ 4 \cdot 4 = 16 \quad \text{и} \quad 2 \cdot 9 = 18 ]

И таким образом: [ 4 \sqrt{16} - 2 \sqrt{81} = 16 - 18 = -2 ]

Ответ: (-2)

в) (10 \sqrt{\frac{81}{100}})

Сначала найдём значение подкоренного выражения: [ \sqrt{\frac{81}{100}} = \frac{\sqrt{81}}{\sqrt{100}} = \frac{9}{10} ]

Теперь умножим: [ 10 \sqrt{\frac{81}{100}} = 10 \cdot \frac{9}{10} = 9 ]

Ответ: (9)

г) (5 \sqrt{\frac{36}{25}})

Сначала найдём значение подкоренного выражения: [ \sqrt{\frac{36}{25}} = \frac{\sqrt{36}}{\sqrt{25}} = \frac{6}{5} ]

Теперь умножим: [ 5 \sqrt{\frac{36}{25}} = 5 \cdot \frac{6}{5} = 6 ]

Ответ: (6)

д) (100 \sqrt{0.04} - 114 \sqrt{0.01})

Сначала найдём значения подкоренных выражений: [ \sqrt{0.04} = 0.2 \quad \text{и} \quad \sqrt{0.01} = 0.1 ]

Теперь подставим эти значения: [ 100 \sqrt{0.04} - 114 \sqrt{0.01} = 100 \cdot 0.2 - 114 \cdot 0.1 ]

Рассчитаем: [ 100 \cdot 0.2 = 20 \quad \text{и} \quad 114 \cdot 0.1 = 11.4 ]

И таким образом: [ 100 \sqrt{0.04} - 114 \sqrt{0.01} = 20 - 11.4 = 8.6 ]

Ответ: (8.6)

е) (1 \frac{4}{7} \cdot \sqrt{4900})

Сначала найдём значение подкоренного выражения: [ \sqrt{4900} = 70 ]

Теперь переведём смешанное число в неправильную дробь: [ 1 \frac{4}{7} = \frac{7 + 4}{7} = \frac{11}{7} ]

Теперь умножим: [ 1 \frac{4}{7} \cdot \sqrt{4900} = \frac{11}{7} \cdot 70 = \frac{11 \cdot 70}{7} = \frac{770}{7} = 110 ]

Ответ: (110)

Надеюсь, это поможет!

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ответил 4 месяца назад

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